Question

a force of 100 n to the right is applied to a soccer ball when it is kicked. an opposite force of 5 n to the left is applied to the soccer ball due to the friction of the grass. what is the net force applied to the object? (1 point)
○ 95 n to the left
○ 105 n to the right
○ 95 n to the right
○ 105 n to the left

Explanation:

Step1: Define forces direction

Let right - direction force be positive. So the applied force \( F_1 = + 100\ N \), and the frictional force (opposite, left - direction) \( F_2=- 5\ N \).

Step2: Calculate net force

The formula for net force \( F_{net}=F_1 + F_2 \). Substitute the values: \( F_{net}=100\ N+( - 5\ N)=100 - 5=95\ N \). Since the result is positive, the net force is in the right direction.

Answer:

95 N to the right