Question

a force of 15 n is applied to a spring, causing it to stretch 0.3 m. what is the spring constant for this particular spring? n/m

Explanation:

Step1: Recall Hooke's Law

Hooke's Law states that the force \( F \) applied to a spring is related to the spring constant \( k \) and the displacement \( x \) by the formula \( F = kx \). We need to solve for \( k \), so we can rearrange the formula to \( k=\frac{F}{x} \).

Step2: Substitute the given values

We are given \( F = 15\space N \) and \( x = 0.3\space m \). Substituting these values into the formula for \( k \), we get \( k=\frac{15}{0.3} \).

Step3: Calculate the value of \( k \)

Calculating \( \frac{15}{0.3} \), we know that dividing by 0.3 is the same as multiplying by \( \frac{10}{3} \), so \( 15\times\frac{10}{3}=50 \).

Answer:

50