Question

the force of an object is equal to its mass multiplied by its acceleration. newton’s second law f = m * a. 1. how much force is needed to accelerate a 1000 - kg car at a rate of 3 m/s²? if your answer is not a whole number round to 2 decimals. no commas in the answer. answer units n kg m/s². 2. if a 70 - kg swimmer pushes off a pool wall with a force of 250 n, at what rate will the swimmer accelerate from the wall? answer units n kg m/s² round to 2 decimals. 3. a weightlifter raises a 200 - kg barbell with an acceleration of 3 m/s². how much force does the weightlifter use to raise the barbell. answer units n kg m/s². 4. a dancer lifts his partner above his head with an acceleration of 2.5 m/s². the dancer exerts a force of 200 n. what is the mass of the partner? answer units n kg m/s². 2) create your own examples in the following space, create your own action / reaction examples. describe event force triangle describe event force triangle

Explanation:

Step1: Identify the formula

We use Newton's second - law formula $F = m\times a$, where $F$ is force in Newtons (N), $m$ is mass in kilograms (kg), and $a$ is acceleration in meters per second squared ($m/s^{2}$).

Step2: Solve problem 1

Given $m = 1000$ kg and $a=3$ $m/s^{2}$. Substitute into the formula: $F=m\times a=1000\times3 = 3000$ N.

Step3: Solve problem 2

Given $F = 250$ N and $m = 70$ kg. Rearrange the formula to $a=\frac{F}{m}$. Then $a=\frac{250}{70}\approx3.57$ $m/s^{2}$.

Step4: Solve problem 3

Given $m = 200$ kg and $a = 3$ $m/s^{2}$. Using $F=m\times a$, we get $F=200\times3=600$ N.

Step5: Solve problem 4

Given $F = 200$ N and $a = 2.5$ $m/s^{2}$. Rearrange the formula to $m=\frac{F}{a}$. Then $m=\frac{200}{2.5}=80$ kg.

Answer:

1. 3000 N
2. 3.57 $m/s^{2}$
3. 600 N
4. 80 kg