Question

the formula for the height, h(t), of a projectile is h(t)= - 4.9t²+vt + h₀, where t is the time in seconds, v is the velocity at which the object is thrown, measured in meters per second, and h₀ is the initial height of the object, measured in meters. annabelle wrote the function h(4)= - 4.9(4)²+(25)(4)+2. what is she trying to find? a. the height after 2 seconds of an object with an initial height of 4 meters, thrown with a velocity of 25 m/s b. the height after 25 seconds of an object with an initial height of 4 meters, thrown with a velocity of 2 m/s c. the height after 4 seconds of an object with an initial height of 25 meters, thrown with a velocity of 2 m/s d. the height after 4 seconds of an object with an initial height of 2 meters, thrown with a velocity of 25 m/s

Explanation:

Step1: Identify the height - time formula

The formula for the height of a projectile is $h(t)=-4.9t^{2}+vt + h_0$, where $t$ is time, $v$ is the initial velocity and $h_0$ is the initial height.

Step2: Analyze the given function $h(4)$

We are given $h(4)=-4.9(4)^{2}+(25)(4)+2$. Here, $t = 4$ seconds, $v = 25$ m/s and $h_0=2$ m. This function is calculating the height of an object at $t = 4$ seconds with an initial height of $2$ meters and an initial velocity of $25$ m/s.

Answer:

D. The height after 4 seconds of an object with an initial height of 2 meters, thrown with a velocity of 25 m/s