Question

in a game of tug of war, team - one pulls to the right with a force of 500 newtons and team - two pulls to the left with a force of 600 newtons. what is the net force? a 100 n, left b 1100 n, right c 100 n, right d 0 n, balanced

Explanation:

Step1: Define forces

Let the force to the right be positive ($F_1 = 500N$) and the force to the left be negative ($F_2=- 600N$).

Step2: Calculate net - force

The net force $F_{net}=F_1 + F_2$. Substitute the values: $F_{net}=500+( - 600)=500 - 600=-100N$. The negative sign indicates the direction is to the left.

Answer:

A. 100 N, left