Question

geometry/transitional math
one - step and two - step equations quiz
solve each equation.

1. $\frac{n}{3}=5$
2. $\frac{x}{9}=\frac{5}{9}$
3. $x - 6 = 0$
4. $-7m=-21$
5. $n - 4=-2$
6. $m + 9 = 5$
7. $p - 8=-12$
8. $x - 3 = 6$
9. $2(n + 1)=14$
10. $-(2 + x)=-1$
11. $-3(4 + x)=-21$
12. $-5+\frac{x}{3}=-2$
13. $-2+\frac{r}{4}=-3$
14. $\frac{k}{2}+3 = 6$
15. $2(-5 + n)=-24$
16. $6x = 36$
17. $r + 6 = 5$
18. $\frac{v}{4}=-9$
19. $r - 6=-10$
20. $-4r=-12$
21. $n + 7 = 8$
22. $m - 7=-15$
23. $3 - 5x = 23$
24. $-5(5 + x)=-65$
25. $5 - 4a = 5$
26. $\frac{n}{3}-2=-2$
27. $-3 - 3b=-9$
28. $-3(a + 4)=-39$
29. $-1+\frac{x}{4}=-2$
30. $-2(3 + x)=10$

Explanation:

Step1: Solve $\frac{n}{3}=5$

Multiply both sides by 3. $n = 5\times3=15$

Step2: Solve $6x = 36$

Divide both sides by 6. $x=\frac{36}{6}=6$

Step3: Solve $\frac{x}{9}=\frac{5}{9}$

Multiply both sides by 9. $x = 5$

Step4: Solve $r + 6=5$

Subtract 6 from both sides. $r=5 - 6=-1$

Step5: Solve $x-6 = 0$

Add 6 to both sides. $x=6$

Step6: Solve $\frac{v}{4}=-9$

Multiply both sides by 4. $v=-9\times4=-36$

Step7: Solve $-7m=-21$

Divide both sides by - 7. $m=\frac{-21}{-7}=3$

Step8: Solve $r - 6=-10$

Add 6 to both sides. $r=-10 + 6=-4$

Step9: Solve $n-4=-2$

Add 4 to both sides. $n=-2 + 4=2$

Step10: Solve $-4r=-12$

Divide both sides by - 4. $r=\frac{-12}{-4}=3$

Step11: Solve $m + 9=5$

Subtract 9 from both sides. $m=5 - 9=-4$

Step12: Solve $n+7=8$

Subtract 7 from both sides. $n=8 - 7=1$

Step13: Solve $p-8=-12$

Add 8 to both sides. $p=-12 + 8=-4$

Step14: Solve $m-7=-15$

Add 7 to both sides. $m=-15 + 7=-8$

Step15: Solve $x-3=6$

Add 3 to both sides. $x=6 + 3=9$

Step16: Solve $3-5x=23$

Subtract 3 from both sides: $-5x=23 - 3=20$. Then divide both sides by - 5. $x=\frac{20}{-5}=-4$

Step17: Solve $2(n + 1)=14$

Divide both sides by 2: $n + 1=7$. Then subtract 1 from both sides. $n=7 - 1=6$

Step18: Solve $-5(5 + x)=-65$

Divide both sides by - 5: $5 + x = 13$. Then subtract 5 from both sides. $x=13 - 5=8$

Step19: Solve $-(2 + x)=-1$

Multiply both sides by - 1: $2 + x = 1$. Then subtract 2 from both sides. $x=1 - 2=-1$

Step20: Solve $5-4a=5$

Subtract 5 from both sides: $-4a=0$. Then divide both sides by - 4. $a = 0$

Step21: Solve $-3(4 + x)=-21$

Divide both sides by - 3: $4 + x = 7$. Then subtract 4 from both sides. $x=7 - 4=3$

Step22: Solve $\frac{n}{3}-2=-2$

Add 2 to both sides: $\frac{n}{3}=0$. Then multiply both sides by 3. $n = 0$

Step23: Solve $-5+\frac{x}{3}=-2$

Add 5 to both sides: $\frac{x}{3}=3$. Then multiply both sides by 3. $x = 9$

Step24: Solve $-3-3b=-9$

Add 3 to both sides: $-3b=-6$. Then divide both sides by - 3. $b = 2$

Step25: Solve $-2+\frac{r}{4}=-3$

Add 2 to both sides: $\frac{r}{4}=-1$. Then multiply both sides by 4. $r=-4$

Step26: Solve $-3(a + 4)=-39$

Divide both sides by - 3: $a + 4 = 13$. Then subtract 4 from both sides. $a=13 - 4=9$

Step27: Solve $\frac{k}{2}+3=6$

Subtract 3 from both sides: $\frac{k}{2}=3$. Then multiply both sides by 2. $k = 6$

Step28: Solve $-1+\frac{x}{4}=-2$

Add 1 to both sides: $\frac{x}{4}=-1$. Then multiply both sides by 4. $x=-4$

Step29: Solve $2(-5 + n)=-24$

Divide both sides by 2: $-5 + n=-12$. Then add 5 to both sides. $n=-12 + 5=-7$

Step30: Solve $-2(3 + x)=10$

Divide both sides by - 2: $3 + x=-5$. Then subtract 3 from both sides. $x=-5 - 3=-8$

Answer:

1. $n = 15$
2. $x = 6$
3. $x = 5$
4. $r=-1$
5. $x = 6$
6. $v=-36$
7. $m = 3$
8. $r=-4$
9. $n = 2$
10. $r = 3$
11. $m=-4$
12. $n = 1$
13. $p=-4$
14. $m=-8$
15. $x = 9$
16. $x=-4$
17. $n = 6$
18. $x = 8$
19. $x=-1$
20. $a = 0$
21. $x = 3$
22. $n = 0$
23. $x = 9$
24. $b = 2$
25. $r=-4$
26. $a = 9$
27. $k = 6$
28. $x=-4$
29. $n=-7$
30. $x=-8$