Question

getting ready: using properties of exponents

1. simplify the expression. write your answer using only positive exponents.

\\(\frac{3g}{4^{-2}} = \square\\)

Explanation:

Step1: Apply negative exponent rule

Recall $a^{-n}=\frac{1}{a^n}$, so $4^{-2}=\frac{1}{4^2}$. Thus:
$\frac{3g}{4^{-2}} = 3g \times 4^2$

Step2: Calculate positive exponent value

Compute $4^2$:
$4^2 = 16$

Step3: Multiply constants

Multiply 3 and 16:
$3 \times 16 = 48$

Answer:

$48g$