Question

1. given: p(e) = 0.27, p(f) = 0.46, and p(e ∩ f) = 0.11 find p(e|f). a) .76 b) .12 c) .88 d) .24 e) .41

Explanation:

Step1: Recall Conditional Probability Formula

The formula for conditional probability is \( P(E|F) = \frac{P(E \cap F)}{P(F)} \).

Step2: Substitute Given Values

We know that \( P(E \cap F) = 0.11 \) and \( P(F) = 0.46 \). Substitute these values into the formula:
\( P(E|F) = \frac{0.11}{0.46} \approx 0.24 \) (rounded to two decimal places).

Answer:

d) .24