Question

given ((x - 7)^2 = 36), select the values of (x). (square) (x = 13) (square) (x = 1) (square) (x = -29) (square) (x = 42) done

Explanation:

Step1: Take square root of both sides

$x-7 = \pm\sqrt{36}$
$x-7 = \pm6$

Step2: Solve for x (positive root)

$x = 7 + 6$
$x = 13$

Step3: Solve for x (negative root)

$x = 7 - 6$
$x = 1$

Answer:

A. x = 13, B. x = 1