Question

given ( k(x) = 8x^3 + 3x ), answer the following:
part 1 of 4
(a) find ( k(-x) ).
( k(-x) = -8x^3 - 3x )
part: 1 / 4
part 2 of 4
(b) find ( -k(x) ).
( -k(x) = square )

Explanation:

Step1: Substitute into -k(x)

$-k(x) = -(8x^3 + 3x)$

Step2: Distribute the negative sign

$-k(x) = -8x^3 - 3x$

Answer:

$-8x^3 - 3x$