Question

1. given:

initial horizontal velocity (vₓ₀): 2.40 m/s
total time (t): 3.90 s
angle (θ): 0°
wanted: distance (x) in m?
distance? m

Explanation:

Step1: Identify horizontal motion formula

For projectile motion with angle \( \theta = 0^\circ \), horizontal velocity \( v_{x0} \) is constant. The horizontal distance \( x \) is given by \( x = v_{x0} \times t \).

Step2: Substitute values

Given \( v_{x0} = 2.40 \, \text{m/s} \) and \( t = 3.90 \, \text{s} \), substitute into the formula: \( x = 2.40 \times 3.90 \).

Step3: Calculate the product

\( 2.40 \times 3.90 = 9.36 \).

Answer:

\( 9.36 \)