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3. given the linear function graph of $y = 3x - 2$, what is the $y$-int…

Question

  1. given the linear function graph of $y = 3x - 2$, what is the $y$-intercept?

$\bigcirc$ $(0, 3)$
$\bigcirc$ $(0, -2)$
$\bigcirc$ $(3, 0)$
$\bigcirc$ $(2, 0)$

Explanation:

Step1: Recall slope-intercept form

A linear function in slope-intercept form is $y = mx + b$, where $b$ is the y-intercept's y-value, and the intercept point is $(0, b)$.

Step2: Match given equation to form

For $y = 3x - 2$, we identify $b = -2$. Thus, the y-intercept is the point $(0, -2)$.

Answer:

(0, -2)