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Question
given: ∠1 and ∠2 a linear pair; ∠2, ∠3, and ∠4 supplementary; prove: m∠1 = m∠3 + m∠4 statements reasons 1. ∠1 and ∠2 a linear pair; ∠2, ∠3, and ∠4 supplementary; 1. given 2. 2. supplement theorem 3. 3. definition of supplementary ∠s 4. m∠2 + m∠3 + m∠4 = 180° 4. 5. m∠1 + m∠2 = m∠2 + m∠3 + m∠4 5. 6. m∠1 = m∠3 + m∠4 6.
Step1: Recall linear - pair property
Since ∠1 and ∠2 are a linear pair, by the Supplement Theorem, ∠1 and ∠2 are supplementary, so \(m\angle1 + m\angle2=180^{\circ}\).
Step2: Define supplementary angles
Because ∠2, ∠3, and ∠4 are supplementary, by the definition of supplementary angles, \(m\angle2 + m\angle3 + m\angle4 = 180^{\circ}\).
Step3: Substitute equal - values
Since \(m\angle1 + m\angle2=180^{\circ}\) and \(m\angle2 + m\angle3 + m\angle4 = 180^{\circ}\), we can substitute to get \(m\angle1 + m\angle2=m\angle2 + m\angle3 + m\angle4\).
Step4: Use subtraction property of equality
Subtract \(m\angle2\) from both sides of the equation \(m\angle1 + m\angle2=m\angle2 + m\angle3 + m\angle4\). We get \(m\angle1=m\angle3 + m\angle4\).
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| Statements | Reasons |
|---|---|
| 2. \(m\angle1 + m\angle2 = 180^{\circ}\) | 2. Supplement Theorem |
| 3. \(m\angle2 + m\angle3 + m\angle4=180^{\circ}\) | 3. Definition of Supplementary ∠'s |
| 4. \(m\angle2 + m\angle3 + m\angle4 = 180^{\circ}\) | 4. Definition of Supplementary ∠'s |
| 5. \(m\angle1 + m\angle2=m\angle2 + m\angle3 + m\angle4\) | 5. Substitution Property of Equality |
| 6. \(m\angle1=m\angle3 + m\angle4\) | 6. Subtraction Property of Equality |