QUESTION IMAGE
Question
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find the product of each pair of conjugates.
- ((x - 7)(x + 7))
- ((2x + 9)(2x - 9))
- ((5x + 3)(5x - 3))
- ((a - b)(a + b))
pg. 58
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Problem 17: \((x - 7)(x + 7)\)
Step1: Identify the formula
We use the difference of squares formula: \((a - b)(a + b)=a^{2}-b^{2}\). Here, \(a = x\) and \(b = 7\).
Step2: Apply the formula
Substitute \(a=x\) and \(b = 7\) into the formula: \(x^{2}-7^{2}\)
Step3: Simplify
Calculate \(7^{2}=49\), so the result is \(x^{2}-49\)
Step1: Identify the formula
Use the difference of squares formula: \((a - b)(a + b)=a^{2}-b^{2}\). Here, \(a = 2x\) and \(b = 9\).
Step2: Apply the formula
Substitute \(a = 2x\) and \(b=9\) into the formula: \((2x)^{2}-9^{2}\)
Step3: Simplify
Calculate \((2x)^{2}=4x^{2}\) and \(9^{2} = 81\), so the result is \(4x^{2}-81\)
Step1: Identify the formula
Use the difference of squares formula: \((a - b)(a + b)=a^{2}-b^{2}\). Here, \(a = 5x\) and \(b = 3\).
Step2: Apply the formula
Substitute \(a = 5x\) and \(b = 3\) into the formula: \((5x)^{2}-3^{2}\)
Step3: Simplify
Calculate \((5x)^{2}=25x^{2}\) and \(3^{2}=9\), so the result is \(25x^{2}-9\)
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\(x^{2}-49\)