Question

grade 6: mrl>chapter 7>chapter test> question #5

1. find the height of the trapezoid.

9 m
area = 121 m²
13 m
□ m
grade 6: mrl>chapter 7>chapter test> question #11

Explanation:

Step1: Recall trapezoid area formula

The area of a trapezoid is given by $A = \frac{1}{2}(b_1 + b_2)h$, where $b_1$ and $b_2$ are the lengths of the two parallel sides, and $h$ is the height.

Step2: Substitute known values

We know $A = 121$, $b_1 = 9$, $b_2 = 13$. Plug these into the formula:
$121 = \frac{1}{2}(9 + 13)h$

Step3: Simplify the sum of bases

Calculate $9 + 13 = 22$, so:
$121 = \frac{1}{2}(22)h$
$121 = 11h$

Step4: Solve for height $h$

Divide both sides by 11:
$h = \frac{121}{11}$

Answer:

11 m