Question

graph the following equation on the coordinate plane: $6x + 3y = -12$. plot two points to graph the line.

Explanation:

Step1: Find x-intercept (y=0)

Substitute $y=0$ into $6x + 3y = -12$:
$$6x + 3(0) = -12$$
$$6x = -12$$
$$x = -2$$
Point: $(-2, 0)$

Step2: Find y-intercept (x=0)

Substitute $x=0$ into $6x + 3y = -12$:
$$6(0) + 3y = -12$$
$$3y = -12$$
$$y = -4$$
Point: $(0, -4)$

Step3: Verify a third point (optional)

Substitute $x=1$ into $6x + 3y = -12$:
$$6(1) + 3y = -12$$
$$3y = -18$$
$$y = -6$$
Point: $(1, -6)$

Answer:

Plot the points $(-2, 0)$ and $(0, -4)$ on the coordinate plane, then draw a straight line through them to represent the equation $6x + 3y = -12$.