Question

graph the following function on the axes provided.
f(x)=\begin{cases}-2x + 4& \text{for }x < - 1\\-5x + 19& \text{for }x>3end{cases}
click and drag to make a line. click the line to delete it. click on an endpoint of a line to change it.

Explanation:

Step1: Find points for $y = - 2x+4$ when $x < - 1$

When $x=-2$, $y=-2\times(-2)+4=4 + 4=8$. We draw an open - circle at the point $(-1,-2\times(-1)+4 = 6)$ (open because $x
eq - 1$) and a line with slope $-2$ passing through points like $(-2,8)$ for $x < - 1$.

Step2: Find points for $y=-5x + 19$ when $x>3$

When $x = 4$, $y=-5\times4+19=-20 + 19=-1$. We draw an open - circle at the point $(3,-5\times3+19 = 4)$ (open because $x
eq3$) and a line with slope $-5$ passing through points like $(4,-1)$ for $x>3$.

Answer:

Graph a line $y=-2x + 4$ for $x < - 1$ with an open - circle at $(-1,6)$ and a line $y=-5x + 19$ for $x>3$ with an open - circle at $(3,4)$.