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Question
graph the following function. give the x- and y-intercepts. f(x)=√(x + 4) - 4 find x axis intercept find y axis intercept
Find X - axis intercept
Step 1: Set \( f(x) = 0 \)
To find the x - intercept, we know that on the x - axis, the value of \( y=f(x) \) is 0. So we set up the equation \( 0=\sqrt{x + 4}-4 \).
Step 2: Solve for \( x \)
First, add 4 to both sides of the equation: \( \sqrt{x + 4}=4 \). Then, square both sides of the equation to get rid of the square root: \( x + 4=4^{2}=16 \). Finally, subtract 4 from both sides: \( x=16 - 4=12 \).
Step 1: Set \( x = 0 \)
To find the y - intercept, we know that on the y - axis, the value of \( x \) is 0. So we substitute \( x = 0 \) into the function \( f(x)=\sqrt{x + 4}-4 \).
Step 2: Calculate \( f(0) \)
\( f(0)=\sqrt{0 + 4}-4=\sqrt{4}-4 = 2-4=-2 \).
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The x - intercept is \( x = 12 \) (the point is \( (12,0) \))