Question

graph the function.
$f(x)=sqrt{x}+2$
plot four points on the graph of the function: the left - most point and three additional points. then click on the graph - a - function button.

Explanation:

Step1: Find the domain

The expression under the square - root must be non - negative. So, $x\geq0$. The leftmost point occurs when $x = 0$.

Step2: Calculate the leftmost point

When $x = 0$, $y=f(0)=\sqrt{0}+2=2$. So the leftmost point is $(0,2)$.

Step3: Choose additional x - values

Let's choose $x = 1$, $x = 4$, and $x = 9$.

Step4: Calculate y - values for additional points

When $x = 1$, $y=f(1)=\sqrt{1}+2=3$. The point is $(1,3)$.
When $x = 4$, $y=f(4)=\sqrt{4}+2=4$. The point is $(4,4)$.
When $x = 9$, $y=f(9)=\sqrt{9}+2=5$. The point is $(9,5)$.

Answer:

The four points are $(0,2)$, $(1,3)$, $(4,4)$, $(9,5)$