Question

graph the image of △jkl after a translation 5 units right and 7 units up.

Explanation:

Step1: Determine translation rule

For a point $(x,y)$ in the coordinate - plane, a translation 5 units right and 7 units up gives the new point $(x + 5,y+7)$.

Step2: Assume coordinates of vertices

Suppose the coordinates of the vertices of $\triangle{JKL}$ are $J(x_J,y_J)$, $K(x_K,y_K)$, $L(x_L,y_L)$. The new coordinates after translation are $J'(x_J + 5,y_J+7)$, $K'(x_K + 5,y_K+7)$, $L'(x_L + 5,y_L+7)$.

Step3: Locate new points on graph

On the given grid, find the original points $J$, $K$, $L$. Then move each point 5 units to the right and 7 units up to mark the new points $J'$, $K'$, $L'$. Connect $J'$, $K'$, $L'$ to form the translated triangle.

Answer:

Graph the new triangle $\triangle{J'K'L'}$ with vertices obtained by translating the vertices of $\triangle{JKL}$ 5 units right and 7 units up. (Since the original coordinates of $J$, $K$, $L$ are not given numerically, the final answer is the instruction to graph the translated triangle as described above.)