Question

graph the image of square jklm after a translation 10 units left and 3 units down.

Explanation:

Step1: Recall translation rule

For a point $(x,y)$, a translation of 10 units left and 3 units down changes it to $(x - 10,y - 3)$.

Step2: Find new coordinates of point J

The coordinates of J are $(0,-2)$. After translation, $x=0 - 10=-10$ and $y=-2 - 3=-5$. So new J is $(-10,-5)$.

Step3: Find new coordinates of point K

The coordinates of K are $(10,-2)$. After translation, $x = 10-10 = 0$ and $y=-2 - 3=-5$. So new K is $(0,-5)$.

Step4: Find new coordinates of point L

The coordinates of L are $(10,8)$. After translation, $x=10 - 10=0$ and $y=8 - 3 = 5$. So new L is $(0,5)$.

Step5: Find new coordinates of point M

The coordinates of M are $(0,8)$. After translation, $x=0 - 10=-10$ and $y=8 - 3 = 5$. So new M is $(-10,5)$.

Step6: Graph the new square

Plot the points $(-10,-5),(0,-5),(0,5),(-10,5)$ and connect them to form the new - square.

Answer:

Graph the square with vertices $(-10,-5),(0,-5),(0,5),(-10,5)$ on the given coordinate - plane.