Question

graph the image of △stu after a translation 2 units right and 6 units down.

Explanation:

Step1: Find coordinates of S, T, U

From the graph:

• \( S(-8, -1) \)
• \( T(-8, 0) \)
• \( U(0, 0) \)

Step2: Apply translation (2 right, 6 down)

Translation rule: \( (x, y) \to (x + 2, y - 6) \)

• For \( S(-8, -1) \):

\( x' = -8 + 2 = -6 \), \( y' = -1 - 6 = -7 \) → \( S'(-6, -7) \)

• For \( T(-8, 0) \):

\( x' = -8 + 2 = -6 \), \( y' = 0 - 6 = -6 \) → \( T'(-6, -6) \)

• For \( U(0, 0) \):

\( x' = 0 + 2 = 2 \), \( y' = 0 - 6 = -6 \) → \( U'(2, -6) \)

Step3: Plot the new points

Plot \( S'(-6, -7) \), \( T'(-6, -6) \), \( U'(2, -6) \) and connect them to form \( \triangle S'T'U' \).

Answer:

The image \( \triangle S'T'U' \) has vertices at \( S'(-6, -7) \), \( T'(-6, -6) \), and \( U'(2, -6) \). (Graphing these points on the coordinate plane completes the translation.)