QUESTION IMAGE
Question
graph the line. \\( y = -3x - 1 \\)
Step1: Identify the slope and y-intercept
The equation of the line is in slope - intercept form \(y = mx + b\), where \(m\) is the slope and \(b\) is the y - intercept. For the equation \(y=-3x - 1\), the slope \(m=-3\) and the y - intercept \(b=-1\). This means the line crosses the y - axis at the point \((0,-1)\).
Step2: Plot the y - intercept
On the coordinate plane, find the point \((0,-1)\) (since when \(x = 0\), \(y=-1\)) and mark it.
Step3: Use the slope to find another point
The slope \(m=-3=\frac{-3}{1}\). The slope is the ratio of the change in \(y\) to the change in \(x\) (\(\frac{\Delta y}{\Delta x}\)). Starting from the y - intercept \((0,-1)\), to find the next point, we move down 3 units (because \(\Delta y=- 3\)) and then 1 unit to the right (because \(\Delta x = 1\)). So from \((0,-1)\), moving down 3 units gives \(y=-1-3=-4\) and moving right 1 unit gives \(x = 0 + 1=1\). So the new point is \((1,-4)\). We can also move up 3 units and left 1 unit from the y - intercept. Moving up 3 units from \((0,-1)\) gives \(y=-1 + 3=2\) and moving left 1 unit gives \(x=0-1=-1\), so the point \((-1,2)\) is also on the line.
Step4: Draw the line
Draw a straight line through the points we have plotted (e.g., \((0,-1)\), \((1,-4)\), \((-1,2)\)) to graph the line \(y=-3x - 1\).
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To graph \(y = - 3x-1\):
- Plot the y - intercept \((0,-1)\).
- Use the slope \(-3\) to find additional points (e.g., \((1,-4)\) or \((-1,2)\)).
- Draw a straight line through the plotted points.