Question

graph the line that has a slope of $\frac{1}{9}$ and includes the point (0, 5). click to select points on the graph.

Explanation:

Step1: Recall the slope - intercept form

The slope - intercept form of a line is $y = mx + b$, where $m$ is the slope and $b$ is the y - intercept. Given $m=\frac{1}{9}$ and the point $(0,5)$ which is the y - intercept (since when $x = 0$, $y=5$), so $b = 5$. The equation of the line is $y=\frac{1}{9}x + 5$.

Step2: Find another point

To graph the line, we can find another point. Let $x=9$. Then $y=\frac{1}{9}\times9+5=1 + 5=6$. So another point on the line is $(9,6)$.

Step3: Graph the line

Plot the points $(0,5)$ and $(9,6)$ on the graph and draw a straight line passing through them.

Answer:

Plot the points $(0,5)$ and $(9,6)$ and draw a straight - line through them.