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graph a relationship in which the value of y is 5 less than half the va…

Question

graph a relationship in which the value of y is 5 less than half the value of x. select two points on the coordinate grid. a line will connect the points.

Explanation:

Step1: Formulate the equation

The relationship is \( y=\frac{1}{2}x - 5 \).

Step2: Find the first point (when \( x = 0 \))

Substitute \( x = 0 \) into the equation: \( y=\frac{1}{2}(0)-5=-5 \). So the point is \( (0, - 5) \).

Step3: Find the second point (when \( x = 10 \))

Substitute \( x = 10 \) into the equation: \( y=\frac{1}{2}(10)-5 = 5 - 5=0 \). So the point is \( (10,0) \). (We can also choose other \( x \) values, like \( x = 2 \), then \( y=\frac{1}{2}(2)-5=1 - 5=-4 \), point \( (2,-4) \), but \( (0,-5) \) and \( (10,0) \) are clear on the grid.)

Answer:

Two points can be \( (0, - 5) \) and \( (10,0) \) (or other valid points from the equation \( y=\frac{1}{2}x - 5 \)). When plotting, mark these points on the coordinate grid and draw a line through them.