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Question
graph △stu with vertices s(-9, -8), t(-3, -8), and u(-9, 5). what is the area of △stu? area = square units
Step1: Find the base length
The points $S(-9,-8)$ and $T(-3,-8)$ have the same $y -$coordinate. The length of the base $ST$ is the absolute - value of the difference in their $x -$coordinates. So, $ST=\vert-3-(-9)\vert=\vert-3 + 9\vert = 6$.
Step2: Find the height length
The points $S(-9,-8)$ and $U(-9,5)$ have the same $x -$coordinate. The height of the triangle from the vertex $U$ to the base $ST$ is the absolute - value of the difference in their $y -$coordinates. So, the height $h=\vert5-(-8)\vert=\vert5 + 8\vert=13$.
Step3: Calculate the area
The area formula for a triangle is $A=\frac{1}{2}\times base\times height$. Substitute the base $b = 6$ and height $h = 13$ into the formula: $A=\frac{1}{2}\times6\times13=39$.
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