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graph △stu with vertices s(-9, -8), t(-3, -8), and u(-9, 5). what is th…

Question

graph △stu with vertices s(-9, -8), t(-3, -8), and u(-9, 5). what is the area of △stu? area = square units

Explanation:

Step1: Identify base and height

The points $S(-9,-8)$ and $T(-3,-8)$ have the same $y -$coordinate. The length of the base $ST$ is the absolute - value of the difference in their $x -$coordinates. $| - 3-(-9)|=| - 3 + 9| = 6$. The points $S(-9,-8)$ and $U(-9,5)$ have the same $x -$coordinate. The height of the triangle from $U$ to the line $ST$ is the absolute - value of the difference in their $y -$coordinates. $|5-(-8)|=|5 + 8| = 13$.

Step2: Apply triangle - area formula

The area formula for a triangle is $A=\frac{1}{2}bh$, where $b$ is the base and $h$ is the height. Substitute $b = 6$ and $h = 13$ into the formula: $A=\frac{1}{2}\times6\times13$.

Step3: Calculate the area

$\frac{1}{2}\times6\times13=3\times13 = 39$.

Answer:

39