Question

graph △tuv with vertices t(6, 1), u(-3, -8), and v(6, -8). what is the area of △tuv? area = square units

Explanation:

Step1: Find the base length

The points $U(-3,-8)$ and $V(6,-8)$ have the same $y$-coordinate. The length of the base $b$ is the absolute - value of the difference in their $x$-coordinates. So, $b=\vert6 - (-3)\vert=\vert6 + 3\vert = 9$.

Step2: Find the height length

The points $T(6,1)$ and $V(6,-8)$ have the same $x$-coordinate. The length of the height $h$ is the absolute - value of the difference in their $y$-coordinates. So, $h=\vert1-(-8)\vert=\vert1 + 8\vert=9$.

Step3: Calculate the area of the triangle

The area formula for a triangle is $A=\frac{1}{2}bh$. Substitute $b = 9$ and $h = 9$ into the formula: $A=\frac{1}{2}\times9\times9=\frac{81}{2}=40.5$.

Answer:

$40.5$