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graphing a quadratic function in vertex form graph ( h(x) = 0.5(x + 2)^…

Question

graphing a quadratic function in vertex form
graph ( h(x) = 0.5(x + 2)^2 - 4 ) by following these steps:
step 1: identify ( a ), ( h ), and ( k )
( a = 0.5 ), ( h = )
options: -2, 2, 4

Explanation:

Step1: Recall vertex form structure

The vertex form of a quadratic function is $h(x)=a(x-h)^2+k$.

Step2: Match given function to form

Given $h(x)=0.5(x+2)^2-4$, rewrite as $h(x)=0.5(x-(-2))^2+(-4)$.

Step3: Identify h value

Compare to vertex form: $h=-2$.

Answer:

$h=-2$