Question

the green light emitted by a stoplight has a wavelength of 527 nm. what is the frequency, in s⁻¹, of this photon? (c = 3.00×10⁸ m/s). answer: ____ hz

Explanation:

Step1: Convert wavelength to meters

The wavelength $\lambda = 527\ nm=527\times10^{- 9}\ m$.

Step2: Use the formula $c = \lambda

u$
We know that the speed of light $c = 3.00\times10^{8}\ m/s$, and from $c=\lambda
u$, we can solve for the frequency $
u=\frac{c}{\lambda}$.
Substitute $c = 3.00\times10^{8}\ m/s$ and $\lambda = 527\times10^{-9}\ m$ into the formula:
$
u=\frac{3.00\times 10^{8}}{527\times10^{-9}}\ s^{-1}\approx5.70\times10^{14}\ s^{-1}$

Answer:

$5.70\times 10^{14}\ Hz$