Question

in a group of pea plants, some individuals have a tall stem and others have a short stem. in this group, the gene for the stem height trait has two alleles. the allele for a short stem (h) is recessive to the allele for a tall stem (h). this punnett square shows a cross between two pea plants. punnett square with rows h, h and columns h, h, cells hh, hh, hh, hh what is the probability that a pea plant produced by this cross will be homozygous dominant for the stem height gene? 0% 25% 50% 75% 100%

Explanation:

Step1: Identify homozygous dominant genotype

Homozygous dominant is $HH$.

Step2: Count total Punnett square outcomes

There are 4 total genotypes: $HH, Hh, Hh, hh$.

Step3: Count favorable outcomes

Only 1 outcome is $HH$.

Step4: Calculate probability

Probability = $\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{1}{4} = 25\%$

Answer:

25%