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Question
the hanger diagram has been updated to focus on 1 group of y + 2. keep going: do the same operation to each side so that y is remaining on the left. then rewrite the equation to solve for y. keep in mind, here you need to do two things. first, show your subtraction. then, rewrite. \\(\frac{3(y + 2)}{3}\\) = \\(\frac{15}{3}\\) \\(y + 2 = 5\\) \\(\square - (y + 2)\\) \\(\square - (5)\\)
Step1: Subtract 2 from both sides
$y + 2 - 2 = 5 - 2$
Step2: Simplify to solve for y
$y = 5 - 2$
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$y = 3$
(The blanks should be filled with $-$ and $2$ respectively, so the operation is $(y+2) - 2$ and $5 - 2$)