Question

hemophilia is a sex-linked recessive trait. make a punnett square for a male parent that does not have hemophilia and a female parent that is a carrier. use $x^h$ for normal and $x^h$ for hemophilia.

Explanation:

Step1: Identify parental genotypes

Non-hemophiliac male: $X^H Y$; Carrier female: $X^H X^h$

Step2: List parental gametes

Male gametes: $X^H$, $Y$; Female gametes: $X^H$, $X^h$

Step3: Build Punnett square

	$X^H$ (Mom)	$X^h$ (Mom)
$Y$ (Dad)	$X^H Y$	$X^h Y$

Step4: Assign to table dropdowns

Top-left cell (Dad $X^H$ + Mom $X^H$): $X^H X^H$ (non-hemophiliac female)
Top-right cell (Dad $X^H$ + Mom $X^h$): $X^H X^h$ (carrier non-hemophiliac female)
Bottom-left cell (Dad $Y$ + Mom $X^H$): $X^H Y$ (non-hemophiliac male)
Bottom-right cell (Dad $Y$ + Mom $X^h$): $X^h Y$ (hemophiliac male)

Answer:

	$X^H$ (Mom)	$X^h$ (Mom)
$Y$ (Dad)	$X^H Y$ <br> (Non-hemophiliac male)	$X^h Y$ <br> (Hemophiliac male)