Question

homework #66 m8,7a q3
unit 4 - lesson 4: two - step equations
date: 1 - 14 - 20
directions: solve and check.

1. $-15 + 5b = -30$
2. $14 = 4a + 6$
3. $15y - 13y - 2y + 3y = 9$
4. $2k - (-20k) + 16k - 13k - 5k = $
5. $\frac{1}{4}d + 17 = 28$
6. $\frac{14 + n}{8} = 22$

explain the steps you used to solve problem number 5.

Explanation:

Step1: Isolate the variable term

Subtract 17 from both sides.
$\frac{1}{4}d + 17 - 17 = 28 - 17$
$\frac{1}{4}d = 11$

Step2: Solve for d

Multiply both sides by 4.
$4 \times \frac{1}{4}d = 11 \times 4$
$d = 44$

Step3: Check the solution

Substitute $d=44$ into original equation.
$\frac{1}{4}(44) + 17 = 11 + 17 = 28$

of solving steps for problem 5:

1. First, rewrite the original equation: $\frac{1}{4}d + 17 = 28$
2. Subtract 17 from both sides to isolate the term with the variable, resulting in $\frac{1}{4}d = 11$
3. Multiply both sides by 4 to solve for $d$, giving $d = 44$
4. Verify by plugging $d=44$ back into the original equation: $\frac{1}{4}(44)+17=11+17=28$, which matches the right-hand side, confirming the solution is correct.

Answer:

$d = 44$

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