Question

homework - complementary angles
due sep 5 by 11:58pm points 10 submitting an external tool
given:
∠a = 6x + 20
∠b = 4x − 1

Explanation:

Step1: Recall complementary angles sum to 90°

Since ∠A and ∠B are complementary (from the right angle symbol), their sum is \( 90^\circ \). So, \( \angle A + \angle B = 90 \). Substitute the given expressions: \( (6x + 20) + (4x - 1) = 90 \).

Step2: Simplify the equation

Combine like terms: \( 6x + 4x + 20 - 1 = 90 \) → \( 10x + 19 = 90 \).

Step3: Solve for x

Subtract 19 from both sides: \( 10x = 90 - 19 \) → \( 10x = 71 \). Then divide by 10: \( x = \frac{71}{10} = 7.1 \). (If we need to find angle measures, we can substitute back, but since the problem's goal isn't clear, assuming solving for x here.)

Answer:

\( x = 7.1 \) (or \( \frac{71}{10} \))