Question

a homozygous green pea plant is mixed with a homozygous yellow pea plant. complete the punnett square. green is the dominant allele.
what percentage of the offspring will be green?
what percentage of the offspring will be yellow?

Explanation:

Step1: Set up alleles

Let G represent the dominant green - allele and g represent the recessive yellow - allele. A homozygous green pea plant has genotype GG and a homozygous yellow pea plant has genotype gg.

Step2: Fill Punnett square

The gametes from the green plant are all G, and the gametes from the yellow plant are all g. When we fill the Punnett square, each box gets one allele from each parent. So all the offspring have the genotype Gg.

Step3: Calculate percentages

Since green (G) is dominant, all offspring with genotype Gg will be green. So 100% of the offspring are green and 0% are yellow.

Answer:

-	g	g
G	Gg	Gg

100
0