Question

1. how did the frequency of the wave change as the wavelength decreased from trial 1 to trial 2?

Explanation:

Step1: Recall wave - speed formula

The wave - speed formula is $v = f\lambda$, where $v$ is the wave speed, $f$ is the frequency, and $\lambda$ is the wavelength. Assuming the wave speed $v$ is constant (which is often the case in a given medium).
We can rewrite the formula as $f=\frac{v}{\lambda}$.

Step2: Analyze the relationship

Since $v$ is constant, when $\lambda$ decreases, according to the formula $f=\frac{v}{\lambda}$, the value of $f$ (frequency) will increase. Because if we have two situations: $f_1=\frac{v}{\lambda_1}$ and $f_2=\frac{v}{\lambda_2}$ with $\lambda_2<\lambda_1$, then $f_2 > f_1$.

Answer:

The frequency of the wave increased as the wavelength decreased from Trial 1 to Trial 2.