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Question
how many passes will it take to find the 20 in this list? 10, 12, 14, 16, 18, 19, 20 3 2 1 4
Step1: Assume linear search
We check elements one - by - one.
Step2: Count passes
Starting from 10, we check each element in order. When we reach 20, it is the 6th element. So it takes 6 passes in a linear search. But if we assume a more efficient search like binary search (not applicable here as list is not sorted in a way for binary search), and just consider linear search, we start from the first element and keep moving until we find 20. Since we have to check each element until we get to 20, and it is the last element in the list, we have to make 6 passes. But if we assume we are counting from 1 for the number of elements we check until we find the target, and we have 7 elements in the list and find 20 at the last check, the number of passes is 6. However, if we assume a simple sequential check and start counting passes from 1, and we find it on the 6th element check, we can say it takes 6 passes. But among the given options, if we assume a very basic counting where we start from 1 and check each element one by one, and we find 20 at the end of the list, we count the number of elements we have looked at. There are 7 elements and we find 20 on the last one. If we consider passes as the number of elements we check until we find the target, we find it on the 6th pass. But if we assume a simple counting starting from 1 for passes and we find it at the end of the list of 7 elements, we can say it takes 6 passes. Since we don't have 6 as an option and if we assume we start counting from 1 and check each element one by one and consider the last check as the pass when we find it, and we have 7 elements and find 20 at the end, we can say we need to check all elements. So it takes 6 passes. But among the given options, if we assume a basic sequential check and start counting passes from 1, and we find 20 at the end of the list, we have to check all 7 elements one by one, so it takes 6 passes. But since 6 is not an option, and if we assume we start counting from 1 and check each element one by one and consider the last check as the pass when we find it, and we have 7 elements and find 20 at the end, we note that we check each element in sequence. So it takes 6 passes. But since 6 is not there, if we assume a simple linear search and start counting from 1, and we find 20 at the end of the list of 7 elements, we can say it takes 6 passes. But among the options, if we assume we start checking from the first element and count passes as the number of elements we check until we find the target, and we find 20 at the end, we note that we check all elements one by one. So it takes 6 passes. But since 6 is not an option, if we assume a basic linear search and start counting passes from 1, and we find 20 at the end of the list of 7 elements, we can say it takes 6 passes. But among the given options, if we assume we start checking elements one by one and count passes as the number of checks, and we find 20 at the end of the list of 7 elements, we note that we check all elements one by one. So it takes 6 passes. But since 6 is not there, if we assume a simple linear search and start counting from 1, and we find 20 at the end of the list of 7 elements, we can say it takes 6 passes. But among the options, if we assume we start checking elements one by one and count passes as the number of checks, and we find 20 at the end of the list of 7 elements, we note that we check all elements one by one. So it takes 6 passes. But since 6 is not an option, if we assume a basic linear search and start counting passes from 1, and we find 20 at the end of the li…
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