QUESTION IMAGE
Question
how many solutions does each equation have?
drag each equation to the correct category in the table. click on the reset button to start over.
| number of solutions | equation |
|---|---|
| exactly one solution | |
| infinitely many solutions |
equations:
$4(m + 4) + 1 = 3(m + 6)$
$3(x + 4) = 3(x + 9)$
$6(a + 2) + 5 = 3 + 2(3a + 4) + 4a$
Step1: Simplify first equation
Expand and rearrange $4(x+3)+2=2(2x+7)$:
$4x+12+2=4x+14$
$4x+14=4x+14$
Subtract $4x$ from both sides: $14=14$
Step2: Simplify second equation
Expand and rearrange $2(x+4)=2(x+7)$:
$2x+8=2x+14$
Subtract $2x$ from both sides: $8=14$
Step3: Simplify third equation
Expand and rearrange $3(x+1)+5=2+3(2x+4)-3x$:
$3x+3+5=2+6x+12-3x$
$3x+8=3x+14$
Subtract $3x$ from both sides: $8=14$
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| Number of Solutions | Equation |
|---|---|
| Exactly one solution | (None of the given equations) |
| Infinitely many solutions | $4(x+3)+2=2(2x+7)$ |