Question

c) $x - 4 = \frac{1}{3}(6x - 54)$
how can you tell if an equation has:
a) no

Explanation:

Step1: Eliminate the fraction

Multiply both sides by 3:
$$3(x - 4) = 6x - 54$$

Step2: Expand left-hand side

Distribute the 3:
$$3x - 12 = 6x - 54$$

Step3: Isolate x terms

Subtract $3x$ from both sides:
$$-12 = 3x - 54$$

Step4: Isolate constant terms

Add 54 to both sides:
$$42 = 3x$$

Step5: Solve for x

Divide by 3:
$$x = \frac{42}{3}$$

Answer:

$x = 14$