Question

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Explanation:

Step1: Analyze the inequality

We start with the inequality \( x + 3 \leq -1 \). Our goal is to isolate \( x \) on one side.

Step2: Subtract 3 from both sides

To isolate \( x \), we subtract 3 from both sides of the inequality. This is a valid operation for inequalities (subtracting the same number from both sides preserves the inequality). So we have:
\[

$$\begin{align*} x + 3 - 3 &\leq -1 - 3\\ x &\leq -4 \end{align*}$$

\]

Step3: Test the solution (optional but shown)

We test \( x = -4 \) in the original inequality. Substitute \( x = -4 \) into \( x + 3 \leq -1 \):
\[
-4 + 3 \leq -1\\
-1 \leq -1
\]
Since \( -1 \) is equal to \( -1 \), the inequality holds true, confirming our solution.

Answer:

The solution to the inequality \( x + 3 \leq -1 \) is \( x \leq -4 \), and when testing \( x = -4 \) in the inequality \( -1 \leq -1 \), the result is TRUE.