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Question
if the hypotenuse in the following 30° - 60° - 90° triangle has length 10 inches, what are the lengths of the two legs?
Step1: Set up equation for hypotenuse
In a 30 - 60 - 90 triangle, if the hypotenuse is $2x$ and it is given as 10 inches, we have $2x = 10$.
Step2: Solve for $x$
Dividing both sides of the equation $2x = 10$ by 2, we get $x=\frac{10}{2}=5$.
Step3: Find lengths of legs
The shorter leg is $x$. So its length is 5 inches. The longer leg is $\sqrt{3}x$. Substituting $x = 5$, we get $\sqrt{3}\times5 = 5\sqrt{3}$ inches.
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The lengths of the two legs are 5 inches and $5\sqrt{3}$ inches.