Question

identify the lower class limits, upper class limits, class width, class midpoints, and class boundaries for the given frequency distribution. also identify the number of individuals included in the summary.
blood platelet count of females (1000 cells/μl) frequency
100 - 199 25
200 - 299 91
300 - 399 26
400 - 499 1
500 - 599 3
identify the lower class limits.
100, 200, 300, 400, 500
(type integers or decimals. do not round. use ascending order.)
identify the upper class limits.
199, 299, 399, 499, 599
(type integers or decimals. do not round. use ascending order.)
identify the class width.
100
(type an integer or a decimal. do not round.)
identify the class midpoints.

(type integers or decimals. do not round. use ascending order.)

Explanation:

Step1: Recall mid - point formula

The formula for the class mid - point is $\text{Mid - point}=\frac{\text{Lower class limit}+\text{Upper class limit}}{2}$.

Step2: Calculate mid - point for 100 - 199

For the class 100 - 199, $\text{Mid - point}=\frac{100 + 199}{2}=\frac{299}{2}=149.5$.

Step3: Calculate mid - point for 200 - 299

For the class 200 - 299, $\text{Mid - point}=\frac{200+299}{2}=\frac{499}{2}=249.5$.

Step4: Calculate mid - point for 300 - 399

For the class 300 - 399, $\text{Mid - point}=\frac{300 + 399}{2}=\frac{699}{2}=349.5$.

Step5: Calculate mid - point for 400 - 499

For the class 400 - 499, $\text{Mid - point}=\frac{400+499}{2}=\frac{899}{2}=449.5$.

Step6: Calculate mid - point for 500 - 599

For the class 500 - 599, $\text{Mid - point}=\frac{500 + 599}{2}=\frac{1099}{2}=549.5$.

Answer:

149.5, 249.5, 349.5, 449.5, 549.5