Question

instructions: use the formula for mass to solve the following problems. round all answers to the correct number of significant figures. show all your work.

mass force acceleration calculations

1 90.4 kg 226 n 2.5 m/s² 226÷2.5 m/s² = 90.4 kg
2 7.6 kg 84.00 n 11 m/s² 84.00 n÷11 m/s² = 7.6 kg
3 33.8 kg 453 n 13.4 m/s² 453 n÷13.4 m/s² = 33.8 kg
4 a bowling ball accelerates 2.35 meters per second squared down the lane when a 15 newton force is applied. calculate the mass of the bowling ball.
mass force acceleration calculations
6.4 kg
5 calculate the mass of a car powered by twin turbines that produce 8,890 newton of thrust if the car has an average acceleration of 3.95 meters per second squared.
mass force acceleration calculations
2250 kg
6 calculate the mass (in kg) of the falcon heavy launch vehicle if a 2.06 x 10⁷ newtons average net force produces an average acceleration of 14.5 meters per second squared. (record the answer in scientific notation and include only the coefficient in the checksum).
mass force acceleration calculations
checksum 2389.22 the checksum is the unrounded total of all correctly calculated and rounded answers in the shaded boxes.

Explanation:

Step1: Recall the formula

The formula for mass is $m=\frac{F}{a}$, where $m$ is mass, $F$ is force and $a$ is acceleration.

Step2: Solve problem 4

Given $F = 15\ N$ and $a=2.35\ m/s^{2}$. Then $m=\frac{15}{2.35}\approx6.38\ kg$.

Step3: Solve problem 5

Given $F = 8890\ N$ and $a = 3.95\ m/s^{2}$. Then $m=\frac{8890}{3.95}=2250.63\ kg\approx2250\ kg$ (rounded to the correct number of significant - figures).

Step4: Solve problem 6

Given $F = 2.06\times10^{7}\ N$ and $a = 14.5\ m/s^{2}$. Then $m=\frac{2.06\times 10^{7}}{14.5}\approx1.42\times10^{6}\ kg$.

Answer:

Problem 4 mass: $6.38\ kg$
Problem 5 mass: $2250\ kg$
Problem 6 mass: $1.42\times10^{6}\ kg$