Question

an irregularly shaped rock was lowered into a graduated cylinder holding a volume of water equal to 50 ml. the height of the water rose to 75 ml. if the mass of the stone was 250 g, what was its density? options: 5 g/ml, 10 g/ml, 15 g/ml, 20 g/ml

Explanation:

Step1: Find the volume of the rock

The volume of the rock is the change in water volume. Initial water volume is 50 mL, final is 75 mL. So volume \( V = 75 - 50 = 25 \) mL.

Step2: Calculate density

Density formula is \(
ho=\frac{m}{V} \), where \( m = 250 \) g and \( V = 25 \) mL. So \(
ho=\frac{250}{25}=10 \) g/mL? Wait, no, wait. Wait, 250 divided by 25 is 10? Wait, no, wait the options: wait, 50 to 75 is 25 mL. Mass is 250 g. So 250/25 = 10? Wait but the green option is 5. Wait, maybe I miscalculated. Wait, 75 - 50 is 25 mL. Mass is 250 g. So density is mass over volume: 250 g / 25 mL = 10 g/mL? Wait but the first option is 5. Wait, maybe I made a mistake. Wait, no, 250 divided by 25 is 10. Wait the purple option is 10 g/mL. Wait, let me check again. Initial volume: 50 mL, final:75 mL. Volume of rock: 75 - 50 = 25 mL. Mass:250 g. Density \(
ho = \frac{m}{V} = \frac{250}{25} = 10 \) g/mL. So the correct option is the purple one: 10 g/mL. Wait, but the green option is 5. Wait, maybe I messed up the volume. Wait, 50 to 75 is 25, right? 75 - 50 = 25. So 250 divided by 25 is 10. So the answer should be 10 g/mL, which is the purple option. Wait, but the user's cursor is on green. Maybe I made a mistake. Wait, no, let's recalculate. 250 g divided by 25 mL is 10 g/mL. So the correct answer is 10 g/mL, which is the second option (purple). Wait, the options are: green:5, purple:10, orange:15, cyan:20. So the correct answer is 10 g/mL, so the option is B. 10 g/mL (assuming the options are labeled A, B, C, D as green, purple, orange, cyan).

Answer:

B. 10 g/mL