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a jar contains 7 red jelly beans, 2 black jelly beans and 6 green jelly…

Question

a jar contains 7 red jelly beans, 2 black jelly beans and 6 green jelly beans. you draw one jelly bean. what is the probability of drawing a red bean?
a. (\frac{7}{15}) \t\t\t\tc. (1)
b. (\frac{1}{15}) \t\t\t\td. (\frac{1}{7})

please select the best answer from the choices provided
○ a
○ b
○ c
○ d

Explanation:

Step1: Calculate total number of jelly beans

To find the total number of jelly beans, we add the number of red, black, and green jelly beans. So, \(7 + 2 + 6 = 15\).

Step2: Calculate probability of red jelly bean

The probability of an event is the number of favorable outcomes (red jelly beans) divided by the total number of possible outcomes (total jelly beans). The number of red jelly beans is 7, and total jelly beans is 15. So the probability is \(\frac{7}{15}\).

Answer:

A. \(\frac{7}{15}\)