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if: (jk = 4x + 3), (jl = 47), and (kl = 9x + 5), find (kl).

Question

if: (jk = 4x + 3), (jl = 47), and (kl = 9x + 5), find (kl).

Explanation:

Step1: Use segment - addition postulate

Since $JL=JK + KL$, we substitute the given expressions: $47=(4x + 3)+(9x + 5)$.

Step2: Combine like - terms

$47 = 4x+9x + 3 + 5$, which simplifies to $47=13x + 8$.

Step3: Solve for $x$

Subtract 8 from both sides: $47−8 = 13x$, so $39 = 13x$. Then divide both sides by 13: $x=\frac{39}{13}=3$.

Step4: Find $KL$

Substitute $x = 3$ into the expression for $KL$. Since $KL=9x + 5$, then $KL=9\times3+5$.
$KL = 27+5=32$.

Answer:

32