Question

keep going. lets try to get \\(\frac{1}{3}f\\) alone on the right side. how could you get rid of the 15 on the right side so that \\(\frac{1}{3}f\\) is alone on the right, while keeping the equation balanced? \\(\frac{2}{3}f + 5 = f + 15\\) \\(\frac{2}{3}f\\) \\(\frac{2}{3}f\\) \\(5 = \frac{1}{3}f + 15\\) subtract 15 from both sides divide both sides by 15 add 15 to both sides

Explanation:

Step1: Identify target equation

We start with the simplified equation:
$$5 = \frac{1}{3}f + 15$$

Step2: Isolate the term with $f$

Subtract 15 from both sides to eliminate the constant on the right.
$$5 - 15 = \frac{1}{3}f + 15 - 15$$
$$-10 = \frac{1}{3}f$$

Answer:

To get $\frac{1}{3}f$ alone on the right side, subtract 15 from both sides, resulting in $\boldsymbol{-10 = \frac{1}{3}f}$.