QUESTION IMAGE
Question
kuta software - infinite geometry
angles in a triangle
find the measure of each angle indicated.
- 65° 57°?
- 40°?
- 20° 130°?
- 85° 50°?
- 137° 102°?
- 35° 100°?
- 30° 20° 130?
- 155° 60°?
Step1: Recall angle - sum property of a triangle
The sum of the interior angles of a triangle is 180°. For exterior - angle problems, an exterior angle of a triangle is equal to the sum of the two non - adjacent interior angles.
Step2: Solve problem 1
Let the unknown angle be \(x\). Using the angle - sum property of a triangle, \(x+65^{\circ}+57^{\circ}=180^{\circ}\). Then \(x = 180^{\circ}-(65^{\circ}+57^{\circ})=180^{\circ}-122^{\circ}=58^{\circ}\).
Step3: Solve problem 2
In a right - triangle (one angle is 90°), let the unknown angle be \(y\). Using the angle - sum property, \(y + 40^{\circ}+90^{\circ}=180^{\circ}\). So \(y=180^{\circ}-(40^{\circ}+90^{\circ}) = 50^{\circ}\).
Step4: Solve problem 3
Let the unknown angle be \(z\). By the angle - sum property, \(z+20^{\circ}+130^{\circ}=180^{\circ}\). Then \(z = 180^{\circ}-(20^{\circ}+130^{\circ})=30^{\circ}\).
Step5: Solve problem 4
Let the unknown angle be \(a\). Using the angle - sum property, \(a + 85^{\circ}+50^{\circ}=180^{\circ}\). So \(a=180^{\circ}-(85^{\circ}+50^{\circ}) = 45^{\circ}\).
Step6: Solve problem 5
The exterior angle is equal to the sum of the two non - adjacent interior angles. Let the exterior angle be \(b\). The two non - adjacent interior angles are \(137^{\circ}-102^{\circ}=35^{\circ}\) and \(102^{\circ}\). So \(b=35^{\circ}+102^{\circ}=137^{\circ}\).
Step7: Solve problem 6
The exterior angle is equal to the sum of the two non - adjacent interior angles. Let the unknown angle be \(c\). The two non - adjacent interior angles are \(100^{\circ}-35^{\circ}=65^{\circ}\) and \(35^{\circ}\). So \(c = 65^{\circ}\).
Step8: Solve problem 7
The exterior angle is equal to the sum of the two non - adjacent interior angles. Let the unknown angle be \(d\). The two non - adjacent interior angles are \(30^{\circ}\) and \(20^{\circ}\). So \(d=30^{\circ}+20^{\circ}=50^{\circ}\).
Step9: Solve problem 8
First, find the interior angle adjacent to the 155° exterior angle. It is \(180^{\circ}-155^{\circ}=25^{\circ}\). Let the unknown angle be \(e\). Using the angle - sum property of a triangle, \(e+25^{\circ}+60^{\circ}=180^{\circ}\). So \(e=180^{\circ}-(25^{\circ}+60^{\circ}) = 95^{\circ}\).
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- \(58^{\circ}\)
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- \(30^{\circ}\)
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- \(137^{\circ}\)
- \(65^{\circ}\)
- \(50^{\circ}\)
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