Question

the length of a rectangle is 8 inches more than the width. the perimeter is 36 inches. find the length and the width of the rectangle. the width of the rectangle is and the length of the rectangle is inches, square inches, cubic inches

Explanation:

Step1: Let the width be $w$ inches.

The length $l = w + 8$ inches.

Step2: Use the perimeter formula $P=2(l + w)$.

Given $P = 36$ inches, so $36=2((w + 8)+w)$.

Step3: Simplify the equation.

First, expand the right - hand side: $36=2(2w + 8)=4w+16$.

Step4: Solve for $w$.

Subtract 16 from both sides: $4w=36 - 16=20$. Then divide both sides by 4, so $w = 5$ inches.

Step5: Find the length.

Since $l=w + 8$, substituting $w = 5$ gives $l=5 + 8=13$ inches.

Answer:

The width of the rectangle is 5 inches and the length of the rectangle is 13 inches.